#include<stdio.h>
#include<conio.h>
#define size 20
#define infi 9999
void prim(int L[][size],int node)
{
int T[size],i,j,k;
int min_dist,v1,v2,total=0;
for(i=1;i<= node;i++)
T[i]=0;
printf("\n--------------------------------");
printf("\n The minimum spanning tree is:");
printf("\n--------------------------------");
T[1]=1;
for(k=2;k<= node;k++)
{
min_dist=infi;
for(i=1;i<= node;i++)
{
for(j=1;j<= node;j++)
{
if(L[i][j]&&((T[i]&&!T[j])||(!T[i]&&T[j])))
{
if(L[i][j] < min_dist)
{
min_dist=L[i][j];
v1=i;
v2=j;
}
}
}
}
printf("\n Edge (%d %d)and weight= %d",v1,v2,min_dist);
T[v1]=T[v2]=1;
total=total+min_dist;
}
printf("\n -----------------------------------");
printf("\n total path Length is= %d",total);
printf("\n ------------------------------------");
}
void main()
{
int L[size][size],node;
int v1,v2,length,i,j,n;
clrscr();
printf("\n--------------------------------------");
printf("\n PRIM`s ALGORITHMS ");
printf("\n--------------------------------------\n");
printf("\n Enter Number of nodes in the Graph:");
scanf("%d",&node);
printf("\n Enter Number of Edges in the Graph:");
scanf("%d",&n);
for(i=1;i<= node;i++)
for(j=1;j<= node;j++)
L[i][j]=0;
printf("\n--------Enter edges and weight--------");
for(i=1;i<= n;i++)
{
printf("\nEnter edge by v1 and v2:");
scanf("%d %d",&v1,&v2);
printf("\nEnter Weight from %d to %d:",v1,v2);
scanf("%d",&length);
L[v1][v2]=L[v2][v1]=length;
}
printf("\n Enter any key to see Minimum Spanning Tree?");
getch();
prim(L,node);
getch();
}
</conio.h></stdio.h>
OUTPUT
----------------------------------------------------
PRIM`s MINIMUM SPANNING TREE ALGORITHM
----------------------------------------------------
Enter Number of nodes in the Graph:7
Enter Number of Edges in the Graph:12
--------Enter edges and length----------
Enter edge in form {v1,v2}:1 2
Enter Length from 1 to 2:1
Enter edge in form {v1,v2}:1 4
Enter Length from 1 to 4:4
Enter edge in form {v1,v2}:2 3
Enter Length from 2 to 3:2
Enter edge in form {v1,v2}:2 4
Enter Length from 2 to 4:6
Enter edge in form {v1,v2}:2 5
Enter Length from 2 to 5:4
Enter edge in form {v1,v2}:3 6
Enter Length from 3 to 6:6
Enter edge in form {v1,v2}:3 5
Enter Length from 3 to 5:5
Enter edge in form {v1,v2}:4 5
Enter Length from 4 to 5:3
Enter edge in form {v1,v2}:4 7
Enter Length from 4 to 7:4
Enter edge in form {v1,v2}:5 6
Enter Length from 5 to 6:8
Enter edge in form {v1,v2}:5 7
Enter Length from 5 to 7:7
Enter edge in form {v1,v2}:6 7
Enter Length from 6 to 7:3
Enter any key to see Minimum Spanning Tree?
----------------------------------------------------
The minimum spanning tree is:
----------------------------------------------------
Edge {1,2} and Weight=1
Edge {2,3} and Weight=2
Edge {1,4} and Weight=4
Edge {4,5} and Weight=3
Edge {4,7} and Weight=4
Edge {6,7} and Weight=3
----------------------------------------------------
Total Minimum path Length is= 17
----------------------------------------------------
#include<conio.h>
#define size 20
#define infi 9999
void prim(int L[][size],int node)
{
int T[size],i,j,k;
int min_dist,v1,v2,total=0;
for(i=1;i<= node;i++)
T[i]=0;
printf("\n--------------------------------");
printf("\n The minimum spanning tree is:");
printf("\n--------------------------------");
T[1]=1;
for(k=2;k<= node;k++)
{
min_dist=infi;
for(i=1;i<= node;i++)
{
for(j=1;j<= node;j++)
{
if(L[i][j]&&((T[i]&&!T[j])||(!T[i]&&T[j])))
{
if(L[i][j] < min_dist)
{
min_dist=L[i][j];
v1=i;
v2=j;
}
}
}
}
printf("\n Edge (%d %d)and weight= %d",v1,v2,min_dist);
T[v1]=T[v2]=1;
total=total+min_dist;
}
printf("\n -----------------------------------");
printf("\n total path Length is= %d",total);
printf("\n ------------------------------------");
}
void main()
{
int L[size][size],node;
int v1,v2,length,i,j,n;
clrscr();
printf("\n--------------------------------------");
printf("\n PRIM`s ALGORITHMS ");
printf("\n--------------------------------------\n");
printf("\n Enter Number of nodes in the Graph:");
scanf("%d",&node);
printf("\n Enter Number of Edges in the Graph:");
scanf("%d",&n);
for(i=1;i<= node;i++)
for(j=1;j<= node;j++)
L[i][j]=0;
printf("\n--------Enter edges and weight--------");
for(i=1;i<= n;i++)
{
printf("\nEnter edge by v1 and v2:");
scanf("%d %d",&v1,&v2);
printf("\nEnter Weight from %d to %d:",v1,v2);
scanf("%d",&length);
L[v1][v2]=L[v2][v1]=length;
}
printf("\n Enter any key to see Minimum Spanning Tree?");
getch();
prim(L,node);
getch();
}
</conio.h></stdio.h>
OUTPUT
----------------------------------------------------
PRIM`s MINIMUM SPANNING TREE ALGORITHM
----------------------------------------------------
Enter Number of nodes in the Graph:7
Enter Number of Edges in the Graph:12
--------Enter edges and length----------
Enter edge in form {v1,v2}:1 2
Enter Length from 1 to 2:1
Enter edge in form {v1,v2}:1 4
Enter Length from 1 to 4:4
Enter edge in form {v1,v2}:2 3
Enter Length from 2 to 3:2
Enter edge in form {v1,v2}:2 4
Enter Length from 2 to 4:6
Enter edge in form {v1,v2}:2 5
Enter Length from 2 to 5:4
Enter edge in form {v1,v2}:3 6
Enter Length from 3 to 6:6
Enter edge in form {v1,v2}:3 5
Enter Length from 3 to 5:5
Enter edge in form {v1,v2}:4 5
Enter Length from 4 to 5:3
Enter edge in form {v1,v2}:4 7
Enter Length from 4 to 7:4
Enter edge in form {v1,v2}:5 6
Enter Length from 5 to 6:8
Enter edge in form {v1,v2}:5 7
Enter Length from 5 to 7:7
Enter edge in form {v1,v2}:6 7
Enter Length from 6 to 7:3
Enter any key to see Minimum Spanning Tree?
----------------------------------------------------
The minimum spanning tree is:
----------------------------------------------------
Edge {1,2} and Weight=1
Edge {2,3} and Weight=2
Edge {1,4} and Weight=4
Edge {4,5} and Weight=3
Edge {4,7} and Weight=4
Edge {6,7} and Weight=3
----------------------------------------------------
Total Minimum path Length is= 17
----------------------------------------------------